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20x^2-130x=200
We move all terms to the left:
20x^2-130x-(200)=0
a = 20; b = -130; c = -200;
Δ = b2-4ac
Δ = -1302-4·20·(-200)
Δ = 32900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{32900}=\sqrt{100*329}=\sqrt{100}*\sqrt{329}=10\sqrt{329}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-130)-10\sqrt{329}}{2*20}=\frac{130-10\sqrt{329}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-130)+10\sqrt{329}}{2*20}=\frac{130+10\sqrt{329}}{40} $
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